![]() ![]() Once the folder is created I copied the data.txt file to the folder with "cp data.txt /tmp/idk". This will give us a permission error that can be bypass by adding the -p option which will create the necessary parent directories in order to create the folder as explained in the mkdir manual page. Then copy the datafile using cp, and rename it using mv (read the manpages!)įirst we have to create a folder under the tmp directory to do this we run "mkdir /tmp/idk". ![]() For this level it may be useful to create a directory under /tmp in which you can work using mkdir. The password for the next level is stored in the file data.txt, which is a hexdump of a file that has been repeatedly compressed. Password: 5Te8Y4drgCRfCx8ugdwuEX8KFC6k2EUu The password is 5Te8Y4drgCRfCx8ugdwuEX8KFC6k2EUu After running that command the output was: The command above send the line to stdout where tr shifts every letter 13 positions. To decrypt the line I ran the command below:Ĭat data.txt | tr '' '' For example, with this encryption the letter a would be replaced with n. In order to decrypt it, I have to replace every letter by the letter 13 positions ahead. The data.txt file contains 1 line that was encrypted with the ROT13 algorithm. The password for the next level is stored in the file data.txt, where all lowercase (a-z) and uppercase (A-Z) letters have been rotated by 13 positions Password: IFukwKGsFW8MOq3IRFqr圎1hxTNEbUPR ![]() The output was the following: The password is IFukwKGsFW8MOq3IRFqr圎1hxTNEbUPR In order to decode the file I ran the command below: The data.txt contains 1 line that was encoded in base64. The password for the next level is stored in the file data.txt, which contains base64 encoded data Password: truKLdjsbJ5g7yyJ2X2R0o3a5HQJFuLk They all start with several = signs and if all of the passwords follow the same format the password should be the last line: truKLdjsbJ5g7yyJ2X2R0o3a5HQJFuLk. To do everything in 1 line I used the command below: The next part is to grep the lines that start with the = sign. In order to sort out the plain text I ran "cat data.txt | string". The password for the next level is stored in the file data.txt in one of the few human-readable strings, beginning with several ‘=’ characters.Īccording to the hint, the file contains both strings and binary data which can make it difficult to read. Password: UsvVyFSfZZWbi6wgC7dAFyFuR6jQQUhR The password is: UsvVyFSfZZWbi6wgC7dAFyFuR6jQQUhR To do this I ran the command below in order to sort the lines alphabetically and then remove all duplicates from the output. The password for the next level is stored in the file data.txt and is the only line of text that occurs only once Password: cvX2JJa4CFALtqS87jk27qwqGhBM9plV Millionth cvX2JJa4CFALtqS87jk27qwqGhBM9plV The command only return 1 line and it contained the password: The hint was that the password is next to the word millionth, so I used the command below to read the file and then grep the word millionth. It was a word followed by some spaces and then a possible password. When I logged into the profile I saw the data.txt file and when I read it a bunch of lines came up and it looked like all of the lines had the same structure. The password for the next level is stored in the file data.txt next to the word millionth. ![]() Password: HKBPTKQnIay4Fw76bEy8PVxKEDQRKTzs When I read the file I found that the password is HKBPTKQnIay4Fw76bEy8PVxKEDQRKTzs With that command we found the file in the following directory: /var/lib/dpkg/info/bandit7.password. I then ran "cat /dev/nullĢ>/dev/null redirects error messages to null so that they do not show on stdout. When I logged into the account and ran "ls" I saw the file. On the bandit website it says that the next password is saved in a file named. Password: boJ9jbbUNNfktd78OOpsqOltutMc3MY1 I tried to use the string from the file to log into bandit1 and it worked. I read the file using “cat readme†and it contained 1 line with the following text: “boJ9jbbUNNfktd78OOpsqOltutMc3MY1â€. The output showed that there is a file named “readmeâ€. While logged into the bandit0 user profile I ran the “ls†command to see if I find any useful files. In their website they give us the username and password for bandit0 and we have to find the password for bandit1 Port: 22 ( As of January 2018 the port is now 2220 ) My preference of choice is MobaXTerm and my second choice is Putty. To start this game and login to every level you must use a SSH Client. ![]()
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